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H3CSE-RS-SW Sample Questions:

1. 交换机 SWA 、 SWB 通过二根光纤千兆以太网链路连接在一起,其中交换机 SWA 上有如下接口配置:
[SWA] interface GigabitEthernet 1/0/1
[SWA-GigabitEthernet1/0/1] gvrp
[SWA-GigabitEthernet1/0/1] port link-type trunk
[SWA-GigabitEthernet1/0/1] port trunk permit vlan 1 10
[SWA] interface GigabitEthernet 1/0/2
[SWA-GigabitEthernet1/0/2] port link-type trunk
[SWA-GigabitEthernet1/0/2] port trunk permit vlan 1 10
如要配置链路聚合将这两条链路聚合在一起,如果 SWB 上配置是正确的,从上述信息可以得知

A) 在 SWA 和 SWB 上都配置了链路聚合后,若 SWA 和 SWB 都在聚合端口上开启 MSTP ,则 GigabitEthernet1/0/1 和 GigabitEthe1/0/2 可以参加转发
B) 在 SWASWB 上都配置了链路聚合后,若 SWA 和 SWB 都在聚合端口上开启 MSTP ,则 GigabitEthe1/0/1 和 GigabitEthe1/0/2 之中有一个会被阻塞
C) 只有在 GigabitEthernet1/0/2 和 Gigabit1/0/1 上允许所有 VLAN 通过,二者才可以加入同一个聚合组
D) 只有将 GigabitEthe1/0/2 的配置改为与 GigabitEthe1/0/1 一致,二者才可以加入同一个聚合组

2. 二台路由器通过局域网连接在一起,组成 VRRP 备份组各接口上配置如下:
[RTA-GigabitEthernet1 /0] display this
Ip address 192.168.0.252 255.255.255.0
Vrrp vrid 1 virtual-ip 192.168.0.254
[RTB-GigabitEthernet1/0] display this
Ip address 192.168.0.253 255.255.255.0
Vrrp vrid 1 virtual-ip 192.168.0.254
从上述信息可以得知

A) RTA , RTB 无法选举出备份组 Master 路由器
B) RTA , RTB 都处于 VRRP Master 状态
C) RTB 为备份组 Master 路由器
D) RTA 为备份组 Master 路由器

3. 作为 SNMP 协议实现的基础, MIB 必须以正确的规则存储和访问。
下列有关存储和访问 MIB 的描述,错误的是。（选择 - 项或多项)

A) MIB 以 SM 树形结构存储
B) MIB 是被管理对象的集合并存储在被管理设备上
C) 网管工作站只能访问那些存储在网管工作站上的 MIB 中的对象
D) 网管工作站只能访问那些存储在被管理设备上的 MIB 中的对象
E) MIB 是被管理对象的集合并存储在网管工作站上

4. 关于 STP 的桥 ID ,下列说法正确的是

A) SWA 和 SWB 的 MAC 地址分别为 00-E0-FC-00-00-11 和 00-E0-FC-11-00-11 ,两者优先级分别为 32768 和 4096 ,则当 SWA 和 SWB 进行环形组网并启用生成树协议后, SWA 将成为根桥
B) 桥 ID 由桥 MAC 地址和优先级字段组成,进行桥 ID 的比较时,先比较 MAC 地址, MAC 地址值小者为优
C) 网络中具有最小桥 ID 的网桥,经过 STP 计算,最终将会成为根桥
D) 桥优先级字段长度为 2 个字节,因此桥优先级的取值范围为 0-65535

5. 图示为经过 STP 计算收敛后的稳定拓扑,则下列说法正确的有

A) 该 BPDU 的发送周期为 HelloTime
B) 该 BPDU 为配置 BPDU ,目的地址为 01-80-C2-00-00-0
C) 端口保存该 BPDU 的老化时间为 MaxAge
D) SWA 为网络中的根桥

Solutions: